Find the electric field due to a point charge in cylindrical-polar coordinates.
\[\vec{E} = \frac{q}{4 \pi \epsilon_0} \frac{\vec{r}}{|\vec{r}|^3}\] I figure \(|\vec{r}|=\sqrt{x^2+y^2+z^2}\) and \(x^2+y^2=p^2\) so \(|\vec{r}|^3=(p^2+z^2)^{\frac{3}{2}}\) But I have no idea what to do with the \(\vec{r}\) on the top
Do I rewrite it in term of the cylindrical coordinate unit vectors? \(\vec{r}=p\hat p + \phi\hat \phi + z\hat z\) But this really doesn't make sense to me, do I even need to include the \(\phi\)? or what simplifications can be done? it's symmetric over all angles of \(\phi\) right? so something should be able to get simplified but i'm not quite sure.
I think that we have to start from the potetial function, namely: \[\varphi \left( r \right) = \frac{q}{r}\] where q is the charge
then you have to apply the subsequent equation: \[{\mathbf{E}} = - \nabla \varphi \] using the cylindrical coordinate
in cylindrical coordinate, we have the subsequent identity: \[\nabla \psi = \left( {\frac{{\partial \psi }}{{\partial r}},\;\frac{1}{r}\frac{{\partial \psi }}{{\partial \theta }},\;\frac{{\partial \psi }}{{\partial z}}} \right)\] where: \[r,\;\theta {\text{ and }}z\] are the cylindrical coordinates
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