Write the equation of the line, in point-slope form, that contains the points (-2, -2) and (2, 2).
@Bookworm14
did you find the slope?
0
lol no
lol yeah
it is \((-2,-2),(2,2)\) right ?
Mhm
from -2 to 2 is right 4, and from -2 to 2 is up four right four, up four slope is \(\frac{4}{4}=0\)
actually it is \[\frac{4}{4}=1\] not zero
also notice that in both coordinates the x and the y are the same
And?
this tells you the equation is \(y=x\)
Okay, I still need the entire equation.
to find slope you must use the formula \[m = \frac{ y2-y1 }{x2-x1 }\] so for this it would be 2- (-2) / 2- (-2) equaling 4/4 or 1 point-slope is in the form of y-y1 = m(x-x1) so for this just substitute your points y- (-2)= 1 (x-x1) now distribute on the "x" side y+2=1x+2 subtract 2 from both sides y=1x or just y=x
is there something not entire in \(\huge y=x\)?
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