Question

Help please..
Radio signals travel at a rate of (3x10^8) meters per second. How many seconds would it take for a radio signal to travel from a satellite to the surface of the earth if the satellite is orbiting at a height of (3.6x10^9) meters?

Answer 1

Hey, can u plz help me @Mehek14

Answer 2

scientific notation?

Answer 3

im not sure they don't say anything

Answer 4

@Mehek14

Answer 5

3.6
since the exponent is 9, move the decimal point 9 units to the right

Answer 6

3600000000. ? @Mehek14

Answer 7

yup
don't need the decimal point at the end. :) GJ

Answer 8

thanks so what do we do next ?

Answer 9

@Mehek14

Answer 10

@ganeshie8

Answer 11

time = distance/speed

Answer 12

you have

distance = (3.6x10^9) meters
speed = (3x10^8) meters per second

simple take the ratio for time :
\[\text{time} = \dfrac{3.6\times 10^9}{3\times 10^8}\]

Answer 13

we're gonna use the rule "PEDMAS" right ?

Answer 14

@ganeshie8

Answer 15

use the exponent rule :
\[\large \dfrac{a^m}{a^n} = a^{m-n}\]

Answer 16

\[\text{time} = \dfrac{3.6\times 10^9}{3\times 10^8} = \dfrac{3.6\times 10^{9-8}}{3} = \dfrac{3.6\times 10^1}{3} = \dfrac{36}{3} = ?\]

Answer 17

12 seconds, i got it thank you very much !! @ganeshie8