Can someone help me out on a question? :)
Do you know the formulas for the volumes of a cylinder and a cone?
watz your qeustion?
yes it is 1/3 pi x r^2 x h
o wait i just saw the attach ment sorry i dont knwo how to help with this one :/
That is for a cone. How about for a cylinder?
its okay sky im sure someone else can help :)
\(\Large V_{cylinder} = \pi r^2 h\) \(\Large V_{cone} = \dfrac{1}{3} \pi r^2 h\)
You know the radius and the height of the cone. Use the formula for the volume of a cone, and find the volume of the cone feeder.
3in
@Chunkymonkay Are you able to find the volume of the cone feeder? Use the formula for the volume of a cone with radius = 3 in. and height = 25 in.
that is how the problem is done.
look at the pic and tell me if you understand it
i am so sorry my computer is running slow. i think the volume of a cylinder is v=pi r^2h
yes @arjund12 i understand a little bit
Let's find the volume of the feeder. It is a cone, wight height = 25 in. and radius = 3 in. \(V_{cone} = \dfrac{1}{3} \times 3.14 \times (3~in.)^2 \times 25~in.\) \(V_{cone} = 235.5~in.^3\)
Now we need to find the height of a cylinder with the same volume as the cone and a radius of 5 in.
yes and do we didvide by 3? to find the height of a cylinder
just look at my pic its explicitly explained there.
\(V_{cylinder} = 3.14 \times (5~in.)^2 \times h\) We know the volume of the cylinder is also 235.5 in^3, so we can write: \(3.14 \times (5~in.)^2 \times h = 235.5~in.^3\) Now we need to solve for h, the height of the cylinder.
\(3.14 \times 25~in.^2 \times h = 235.5~in.^3\) \(78.5 ~in^2 h = 235.5 ~in.^3\) \(h = \dfrac{235.5~in.^3}{78.5~in.^2} \) \(h = 3~in.\)
The height of the cylinder is 3 in.
okay thanks everyone
i dont get a medal ? for helping you hahaha
You're welcome.
No problem any time, if you have any more problems i can help you with feel to ask. If you need one-to-one help you can always email at mathutor101@gmail.com
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