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Mathematics 7 Online
OpenStudy (chunkymonkay):

Can someone help me out on a question? :)

OpenStudy (chunkymonkay):

OpenStudy (mathstudent55):

Do you know the formulas for the volumes of a cylinder and a cone?

OpenStudy (sky_guy02):

watz your qeustion?

OpenStudy (chunkymonkay):

yes it is 1/3 pi x r^2 x h

OpenStudy (sky_guy02):

o wait i just saw the attach ment sorry i dont knwo how to help with this one :/

OpenStudy (mathstudent55):

That is for a cone. How about for a cylinder?

OpenStudy (chunkymonkay):

its okay sky im sure someone else can help :)

OpenStudy (mathstudent55):

\(\Large V_{cylinder} = \pi r^2 h\) \(\Large V_{cone} = \dfrac{1}{3} \pi r^2 h\)

OpenStudy (mathstudent55):

You know the radius and the height of the cone. Use the formula for the volume of a cone, and find the volume of the cone feeder.

OpenStudy (anonymous):

3in

OpenStudy (mathstudent55):

@Chunkymonkay Are you able to find the volume of the cone feeder? Use the formula for the volume of a cone with radius = 3 in. and height = 25 in.

OpenStudy (anonymous):

OpenStudy (anonymous):

that is how the problem is done.

OpenStudy (anonymous):

look at the pic and tell me if you understand it

OpenStudy (chunkymonkay):

i am so sorry my computer is running slow. i think the volume of a cylinder is v=pi r^2h

OpenStudy (chunkymonkay):

yes @arjund12 i understand a little bit

OpenStudy (mathstudent55):

Let's find the volume of the feeder. It is a cone, wight height = 25 in. and radius = 3 in. \(V_{cone} = \dfrac{1}{3} \times 3.14 \times (3~in.)^2 \times 25~in.\) \(V_{cone} = 235.5~in.^3\)

OpenStudy (mathstudent55):

Now we need to find the height of a cylinder with the same volume as the cone and a radius of 5 in.

OpenStudy (chunkymonkay):

yes and do we didvide by 3? to find the height of a cylinder

OpenStudy (anonymous):

just look at my pic its explicitly explained there.

OpenStudy (mathstudent55):

\(V_{cylinder} = 3.14 \times (5~in.)^2 \times h\) We know the volume of the cylinder is also 235.5 in^3, so we can write: \(3.14 \times (5~in.)^2 \times h = 235.5~in.^3\) Now we need to solve for h, the height of the cylinder.

OpenStudy (mathstudent55):

\(3.14 \times 25~in.^2 \times h = 235.5~in.^3\) \(78.5 ~in^2 h = 235.5 ~in.^3\) \(h = \dfrac{235.5~in.^3}{78.5~in.^2} \) \(h = 3~in.\)

OpenStudy (mathstudent55):

The height of the cylinder is 3 in.

OpenStudy (chunkymonkay):

okay thanks everyone

OpenStudy (anonymous):

i dont get a medal ? for helping you hahaha

OpenStudy (mathstudent55):

You're welcome.

OpenStudy (anonymous):

No problem any time, if you have any more problems i can help you with feel to ask. If you need one-to-one help you can always email at mathutor101@gmail.com

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