Can yall help me out with this 8. p to p' (2, -6) for the glide reflection where the translation is (x, y) to (x+2, y-2) and the line of reflection is y= -x. what are the coordinates of P? (11, -3) (4, 0) (-11,3) (-4, 0)
do you have a graph?
no
um well lets see
here ill get you a gragh
try it with this
@Bghostrider2
sorry chrome crashed
and ok
dude i have know idea how to do the problem
hold on gonna switch to explorer
okay well um give me just 1 minute and ill get back to you
okay
alright im back
okay so first try and graph the problem on the graph paper
my main problem is the y=-x...I don't know hw to change the coordinates with it
when you do go ahead and tell me what point on the graph reflects (2,-6)
no put all the points on the graph and then see what one reflects that problem
there are only 2 points
even A,B,C,and D put those on the graph as well
ok I put them on the graph
now what one reflects the point (2,-6)
none
okay then what i would do is put the points in the equation and see what you get
okay well im also sort of confused lets see if we can find some one that will know how to set up the equation
would it be option A
uh yes actualy i just set it up and i got a also
well....it wasn't a
so we started at a point (x,y) and we want to end up at (2,-6) Well we can go backwards from that point back through operations so let's back through the reflection over y=-x that is if you have (x,y) then you will have (-y,-x) if you reflect it over that line. So when you reflect (2,-6) about y=-x what point do you get? Once you find that point we have to take back through the translation to get where you started at.
end point (2,-6) after reflection through y=-x we have (6,-2) I will do the reflection part for you now we need to figure out what is x and what is y when (6,-2)=(x+2,y-2) you just have two equations to solve now
it was b
exactly right good job
since 6=x+2 gives x=4 and -2=y-2 gives y=0
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