Question

Can someone help me here?

Solve for x and y. Be prepared to explain what theorem or postulate you used.

Answer 1

It isnt going straight through sadly, so no its not 45-45

Answer 2

@LeofisTaylor

Answer 3

Ok so say we have the third side marked as \(z\):

We can use the Pythagorean theorem and say
$$
\begin{array}{ll|ll}
x^2 = y^2 + 9^2 &&& z^2 = y^2 + 3^2\\
x^2 = y^2 + 81 &&& z^2 = y^2 + 9
\end{array}
\\ \; \\
\begin{array}{cccl}
x^2 &+ &z^2 &= (9 + 3)^2 \\
(y^2 + 81) &+ &(y^2 + 9) &= 12^2
\end{array}\\
2y^2 + 90 = 144 \\
y^2 = \frac{144 - 90}{2} = \frac{54}{2} = 27 \implies y = \sqrt{27} \\
x^2 = y^2 + 81 \implies x^2 = 27 + 81= 108 \implies x = \sqrt{108}
$$