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Mathematics 7 Online
OpenStudy (anonymous):

Geometry question: I will post the question in an image file.

OpenStudy (anonymous):

OpenStudy (anonymous):

I'm not sure how to approach this problem. Ratios or proportions?

ganeshie8 (ganeshie8):

for length BC, you may use law of sines in triangles DBE and EBC

OpenStudy (anonymous):

Okay, please give me a moment to compute.

ganeshie8 (ganeshie8):

In \(\triangle DBE\) apply law of sines\[\dfrac{12}{\sin \angle BED} = \dfrac{4}{\sin \angle DBE}\] In \(\triangle EBC\) apply law of sines\[\dfrac{BC}{\sin \angle BEC} = \dfrac{5}{\sin \angle EBC}\]

ganeshie8 (ganeshie8):

Notice we're given \(\angle DBE \cong \angle EBC \) and also we have \(\sin \angle BED = \sin\angle BEC\) (why ? ) so we get : \[\dfrac{12}{BC} = \dfrac{4}{5}\] solve \(BC\)

OpenStudy (anonymous):

sin<BED = sin<BEC becase <BEC = 180degress - <BED, and sinx = sin(180degrees - x) because on the unit circle the right triangle with angle x and angle 180degrees - x has the same reference angle and the same height of sin(x).

OpenStudy (anonymous):

BC = 15 :)

ganeshie8 (ganeshie8):

Exactly! another way to look at it is ``` sin(180-x) = sin180cosx - cos180sinx = 0*cosx - (-1)sinx = sinx ```

ganeshie8 (ganeshie8):

i hope you can find other lengths :)

OpenStudy (anonymous):

I think I can take it from here! Thanks for your help!!! @ganeshie8

ganeshie8 (ganeshie8):

sounds good ;) finding BE length can be tricky.. just holler if you get stuck !

OpenStudy (anonymous):

Hi @ganeshie8, what did you get for BE and AD? Using law of sines, cosines, and a system of equations, I calculated the length BE = 4sqrt(10), and the length AD = 4(3sqrt(10) + 5)/23. Just checking to see if anyone else is getting the same thing, thanks! -ceboski

OpenStudy (mathstudent55):

You need the "triangle angle bisector theorem." |dw:1425839330760:dw|

OpenStudy (mathstudent55):

The angle bisector of an angle of a triangle divides the opposite side into two segments whose lengths are proportional to their respective adjacent sides.

OpenStudy (mathstudent55):

For the figure above, this theorem means that the following proportion is true: Segment AD bisects angle BAC. Then, \(\dfrac{BD}{AB} = \dfrac{CD}{AC}\)

OpenStudy (mathstudent55):

Using the theorem, you can find BC. Use triangle DBC. Then \(\dfrac{DE}{BD} = \dfrac{EC}{BC} \) The only unknown is BC, so you can find it.

OpenStudy (anonymous):

@mathstudent55 , But BC is not the only unknown! BE, and AD are also unknown. :( Thanks for the tip! Using Triangle Angle Bisector Theorem as you suggested, I find 4/12 = 5/BC, which means BC = 15.

OpenStudy (anonymous):

But is it possible to use the triangle angle bisector theorem to find unknowns BE and AD?

OpenStudy (mathstudent55):

I don't see how. I can use the triangle angle bisector theorem only to find BC.

OpenStudy (anonymous):

Hi everyone, I got the answer using Stewart's Theorem and the Pythagorean Theorem. BC = 15, BE = 4sqrt(10), AD = 4, and AB = 4sqrt(10). Thanks @mathstudent55, @ganeshie8 and to everyone who participated in this problem! -@cebroski

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