Geometry question: I will post the question in an image file.
I'm not sure how to approach this problem. Ratios or proportions?
for length BC, you may use law of sines in triangles DBE and EBC
Okay, please give me a moment to compute.
In \(\triangle DBE\) apply law of sines\[\dfrac{12}{\sin \angle BED} = \dfrac{4}{\sin \angle DBE}\] In \(\triangle EBC\) apply law of sines\[\dfrac{BC}{\sin \angle BEC} = \dfrac{5}{\sin \angle EBC}\]
Notice we're given \(\angle DBE \cong \angle EBC \) and also we have \(\sin \angle BED = \sin\angle BEC\) (why ? ) so we get : \[\dfrac{12}{BC} = \dfrac{4}{5}\] solve \(BC\)
sin<BED = sin<BEC becase <BEC = 180degress - <BED, and sinx = sin(180degrees - x) because on the unit circle the right triangle with angle x and angle 180degrees - x has the same reference angle and the same height of sin(x).
BC = 15 :)
Exactly! another way to look at it is ``` sin(180-x) = sin180cosx - cos180sinx = 0*cosx - (-1)sinx = sinx ```
i hope you can find other lengths :)
I think I can take it from here! Thanks for your help!!! @ganeshie8
sounds good ;) finding BE length can be tricky.. just holler if you get stuck !
Hi @ganeshie8, what did you get for BE and AD? Using law of sines, cosines, and a system of equations, I calculated the length BE = 4sqrt(10), and the length AD = 4(3sqrt(10) + 5)/23. Just checking to see if anyone else is getting the same thing, thanks! -ceboski
You need the "triangle angle bisector theorem." |dw:1425839330760:dw|
The angle bisector of an angle of a triangle divides the opposite side into two segments whose lengths are proportional to their respective adjacent sides.
For the figure above, this theorem means that the following proportion is true: Segment AD bisects angle BAC. Then, \(\dfrac{BD}{AB} = \dfrac{CD}{AC}\)
Using the theorem, you can find BC. Use triangle DBC. Then \(\dfrac{DE}{BD} = \dfrac{EC}{BC} \) The only unknown is BC, so you can find it.
@mathstudent55 , But BC is not the only unknown! BE, and AD are also unknown. :( Thanks for the tip! Using Triangle Angle Bisector Theorem as you suggested, I find 4/12 = 5/BC, which means BC = 15.
But is it possible to use the triangle angle bisector theorem to find unknowns BE and AD?
I don't see how. I can use the triangle angle bisector theorem only to find BC.
Hi everyone, I got the answer using Stewart's Theorem and the Pythagorean Theorem. BC = 15, BE = 4sqrt(10), AD = 4, and AB = 4sqrt(10). Thanks @mathstudent55, @ganeshie8 and to everyone who participated in this problem! -@cebroski
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