Question

Hi, everyone! I just finished a warm-up and instruction for my next Chemistry unit. However, I am having trouble with this homework-assignment question.

A sample of tin (Cp = 0.227 J/gC) is placed in a freezer. Its temperature decreases from 15.0 to 10.0C as it releases 543 J of energy. What is the mass of the sample? Round your answer to three significant figures.

Please help me understand this; thanks!

Answer 1

\(\sf energy~(heat)=mass*specific~heat~capacity*change~in~temperature\)

Answer 2

Thanks. I'll use that equation.

Would it be:

543 J = m x 25.0 C x 5 C?

Answer 3

almost, the specific heat capacity has the symbol \(C_p\), look at your question again

Answer 4

Okay thanks. I'll try it again. Thanks for bearing with me!

543 J = m x 0.227 x 5

Answer 5

that's right! no problem

dont forget to round

Answer 6

I cannot thank you enough! I appreciate your help. I'll definitely give you a medal!

If I have another question in Chemistry, will you give me permission to please tag your name? (:

Answer 7

Also, I used that equation and this was my work:

543 = m x .227 x 5

543 = m x 1.135

543 + 1.135 = 478.41

m = 478.41

The actual answer was 95.7g. What did I do wrong? Thanks (:

Answer 8

you messed up the algebra

\(543 = m * 1.135\)

\(\dfrac{543}{1.135} = m \)

Answer 9

\[543\div1.135=478.41\]

Right? How do I get the 95.7 from there? Thanks (:

I'm sorry for all of the questions!

Answer 10

oh, sorry i thought you just did the algebra wrong. that is the answer

Answer 11

No problem. Thank you. Unfortunately, the actual answer was 95.7. I'm not sure what I did wrong.

Answer 12

It's not. you must've made an error copying it down or the book youre getting this off made a mistake. :S

Answer 13

Okay. I'll ask my teacher tomorrow (: Thank you for your time, @aaronq! You've been awesome.

Answer 14

no problem! hope you get this cleared up