Mathematics
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OpenStudy (cenaida):
In the equation 3x + 4y = 9, find x if 2y = 6.
A. -2
B. -1
C. 0
D. 1
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OpenStudy (freckles):
if 2y=6 then 4y=2(6)=?
OpenStudy (freckles):
then insert that number in place of 4y
and solve for 3x
then x
OpenStudy (cenaida):
is it 0?
OpenStudy (freckles):
let's go in little bitty steps
OpenStudy (freckles):
2y=6
so if I multiply 2 on both sides
I get
2(2y)=2(6)
so 4y=?
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OpenStudy (cenaida):
12?
OpenStudy (freckles):
perfect!:)
\[3x+4y=9 \\ 3x+12=9 \text{ solve this equation for } x \]
OpenStudy (freckles):
So I replaced 4y with 12
OpenStudy (freckles):
now all have to do is solve 3x+12=9 for x
Here is one step 3x=9-12
OpenStudy (cenaida):
what do i do?
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OpenStudy (freckles):
you are solving for x
OpenStudy (freckles):
you had 3x+12=9
I subtracted 12 on both sides for you
and gave you 3x=9-12
OpenStudy (freckles):
find the difference of 9 and 12
then divide both sides by 3 to get x by itself
OpenStudy (cenaida):
9*3=27 12*3=36
OpenStudy (freckles):
9-12 is -3 isn't it?
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OpenStudy (cenaida):
yes
OpenStudy (freckles):
3x+12=9
Subtracted 12 on both sides
3x=9-12
so
then 3x=-3
OpenStudy (freckles):
now I actually gave you the last step to perform
which was to divide both sides by 3
OpenStudy (cenaida):
9?
OpenStudy (freckles):
are you not wanting to divide?
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OpenStudy (freckles):
\[3x=-3 \\ \text{ divide both sides by 3 } \\ \frac{3x}{3}=\frac{-3}{3} \\ x=\frac{-3}{3}\]
OpenStudy (freckles):
how many times does 3 go into -3?
OpenStudy (cenaida):
1
OpenStudy (freckles):
well -1 times
OpenStudy (freckles):
-3/3 is -1
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OpenStudy (freckles):
not 9 or -9
OpenStudy (freckles):
-3(3)=-9 but we had -3/3
OpenStudy (cenaida):
ok..thanks so much!