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Mathematics 14 Online
OpenStudy (anonymous):

Question in pic file below!*

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

\[\int\limits_0^4 f'(x) dx = f(4) - f(0)\]

ganeshie8 (ganeshie8):

you can work the left side integral using geometry look at the given diagram, whats the area under graph between x=0 and x=4 ?

OpenStudy (anonymous):

the area under graph between x=0 & x=4 is 2

ganeshie8 (ganeshie8):

ganeshie8 (ganeshie8):

Try again

OpenStudy (anonymous):

4*

ganeshie8 (ganeshie8):

Yes!

ganeshie8 (ganeshie8):

\[\int\limits_0^4 f'(x) dx = f(4) - f(0)\] so the value of ntegral on left hand side equals \(4\) : \[4= f(4) - f(0)\]

ganeshie8 (ganeshie8):

and you're given the value of \(f(4)\) plug that in and solve \(f(0)\)

OpenStudy (anonymous):

2

ganeshie8 (ganeshie8):

f(0) = 2 is right !

OpenStudy (anonymous):

thanks!!!!!!

ganeshie8 (ganeshie8):

yw

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