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Mathematics 14 Online
OpenStudy (anonymous):

MEDAL! *question in pic file below*

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

what do you think ?

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

Nope. Keep in mind the given graph is NOT f(x). It is f'(x)

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

Nope. By asking "what do you think", I don't mean to make a guess... I was expecting some explanation/justification for why you pick a certain option. Without that I wont know what exactly you're finding difficult about the problem :/

OpenStudy (anonymous):

kk, i think its "f is increasing on the interval from x=-3 to x=1" because the graph

ganeshie8 (ganeshie8):

Look at the graph between x=-3 and x=1 it stays above x axis. that means f'(x) is positive, yes ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

+

ganeshie8 (ganeshie8):

what does f'(x) > 0 tell you about f(x) ?

ganeshie8 (ganeshie8):

f'(x) > 0, which means the first derivative is geater than 0 tells us that f(x) is "increasing"

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

good question, again that graph is f'(x) that highlighted part is above x axis, so that means positive, yes ?

ganeshie8 (ganeshie8):

f'(x) is positive means f(x) is increasing.

OpenStudy (anonymous):

kk

ganeshie8 (ganeshie8):

for example : f(x) = x^2 f'(x) = x^3/3 f'(x) is positive when x > 0, so f(x) will be increasing when x > 0

OpenStudy (anonymous):

:) thank u!

ganeshie8 (ganeshie8):

yw! takes some time to fully make sense of these..

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