Question

Compare the graphs of the inverse variations y=-0.2/x and y=-0.3/x. please provide at least 3 comparisons

Answer 1

switch x and y around then solve for y

Answer 2

@CoconutJJ You're talking about inverse functions, the question is about inverse variations =p
Here is a graph of both, you can see they are quite alike:
http://www.wolframalpha.com/input/?i=graph+y+%3D+-0.2%2Fx%2C+y+%3D+-0.3%2Fx
You can tell that the graph of \(y = \frac{0.3}{x}\) is slightly farther away from zero compared to \(y = \frac{0.2}{x}\).
Besides that they are both have shape of hyperbola, they both has an asymptote at x=0 where they approach \(\infty\) when approaching 0 from the right and \(-\infty\) from the left, and they both have a horizontal asymptote at y=0

Answer 3

so how will it be written? x will be 1,2.3 and y will be -0.20, -0.4, -0.60?

Answer 4

since x increases and y decreases

Answer 5

I made a mistake. I analyzed \(y=\frac{0.2}{x}\) and \(y=\frac{0.3}{x}\) while it is \(y = -\frac{0.2}{x}\) and \(y=-\frac{0.3}{x}\). So the signs are swapped.
That means they both approach \(-\infty\) when approaching zero from the right (instead of \(\infty\)) and approach \(\infty\) when approaching zero from the left (instead of \(-\infty\)).

You mean x will be 1, 2, 3...?
Well in that case we can take several samples of \(y=\frac{0.2}{x}\)
$$
\begin{array}{c|cl}
x&&y \\ \hline
0.125 & -\frac{0.2}{0.125} &= -1.6\\ \hline
0.25 & -\frac{0.2}{0.25} &= -0.8 \\\hline
0.5 & -\frac{0.2}{0.5} &= -0.4 \\\hline
1 & -\frac{0.2}{1} &= -0.2 \\\hline
2 & -\frac{0.2}{2} &= -0.1 \\\hline
3 & -\frac{0.2}{3} &= -0.0666 \dots \\\hline
4 & -\frac{0.2}{4} &= -0.05
\end{array}
$$You can add more values for \(x\) (perhaps a couple of negative ones as well) or make a similar table for \(y=\frac{0.3}{x}\)
Hope it helps =)

Answer 6

thank you so so much!

Answer 7

You're welcome =)