Solve the matrix!
|dw:1425747652317:dw|
how can i eliminate B from the 1st collumn?
where A B and C are constants
...and V
Is this the matrix? \[ \begin{bmatrix} 0&0&A&1&V\\ 0&1&0&1&0\\ A&1&0&0&0\\ B&0&C&0&0 \end{bmatrix} \]
yes!
Does A=0?
no
please swap the first row with the third row first \[\left( {\begin{array}{*{20}{c}} A&1&0&0 \\ 0&1&0&1 \\ 0&0&A&1 \\ B&0&C&0 \end{array}\quad \begin{array}{*{20}{c}} 0 \\ 0 \\ V \\ 0 \end{array}} \right)\]
A is equal to some positive distance divided by 2 and B and C are equal to some viscosities
Are all constants not equal to 0?
Are they known constants or unknown constants?
then replace the fourth row with this row: \[\left( {B\;0\;C\;0\;0} \right) - \frac{B}{A}\left( {A\;1\;0\;0\;0} \right) = ...?\]
they are unknown constants
Just do Gaussian elimination. Nothing special but cumbersome.
I'm not sure how to eliminate the constants. If I could see an example I could probably understand it for future use.
\[\left( {B\;0\;C\;0\;0} \right) - \frac{B}{A}\left( {A\;1\;0\;0\;0} \right) = \left( {0\; - \frac{B}{A}\;C\;0\;0} \right)\quad \]
As the constants are not equal to zero, just multiply the whole row by the inverse of that constant.
Oh, I see. Could you do a little more so I can get the hang of it. Thank you Michele_Laino
@Michele_Laino
For example: \[ \frac{1}{A} \begin{bmatrix} A&1&0&0&0 \end{bmatrix} = \begin{bmatrix} 1&\frac{1}{A}&0&0&0 \end{bmatrix} \]
your Matrix at the first step of the Gaussian method will be this: \[\left( {\begin{array}{*{20}{c}} A&1&0&0 \\ 0&1&0&1 \\ 0&0&A&1 \\ 0&{ - \frac{B}{A}}&C&0 \end{array}\quad \begin{array}{*{20}{c}} 0 \\ 0 \\ V \\ 0 \end{array}} \right)\]
\[ \begin{bmatrix} 1&\frac{1}{A}&0&0&0\\ 0&1&0&1&0\\ 0&0&A&1&V\\ B&0&C&0&0 \end{bmatrix} \\ R_4-BR_1 \\ \begin{bmatrix} 1&\frac{1}{A}&0&0&0\\ 0&1&0&1&0\\ 0&0&A&1&V\\ 0&-\frac{B}{A}&C&0&0 \end{bmatrix} \]
Thank you both I understand now!
Thank you! :) @znimon
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