A sample of nickel is heated to 95.0°C and placed in a coffee-cup calorimeter. If the 50.0 g of water in the calorimeter is initially 22.3°C and warms to 25.4°C, what mass of nickel was heated? (The specific heat of nickel is 0.444 J/°C g and water is 4.18 J/°C g).

A. 15.4 g
B. 57.5 g
C. 2.1 g
D. 21.0 g

Question

A sample of nickel is heated to 95.0°C and placed in a coffee-cup calorimeter. If the 50.0 g of water in the calorimeter is initially 22.3°C and warms to 25.4°C, what mass of nickel was heated? (The specific heat of nickel is 0.444 J/°C g and water is 4.18 J/°C g). 

A.	15.4 g 
B.	57.5 g 
C.	2.1 g 
D.	21.0 g

vera_ewing · Answer

@Somy

somy · Answer

Q = mc Delta T 
use m (mass) of water, c (specific heat) of water and temperature change of water 
Find the Q 

then use the Q value and the formula again 
but this time use temperature change of Nickel which is from 95 to 25.4 
and use c (specific heat of nickel) so 
u will have value of Q found earlier
u have temp change of nickel and u have specific heat 
thus find mass using same formula

vera_ewing · Answer

so what would the answer be?

somy · Answer

i dont know, calculate it to find out

vera_ewing · Answer

can you show me how to?

somy · Answer

Firstly use this formula 
Q= mc Delta T 
m= mass of water 
c= specific heat of water 
Delta T is temperature change = 25.4°C - 22.3°C = get it 

and so get the answer for Q

vera_ewing · Answer

so it's C?

somy · Answer

did you try calculating and got C?

vera_ewing · Answer

well i actually got 03.1

vera_ewing · Answer

which is none of the answer choices lol

somy · Answer

you haven't finished tho

somy · Answer

+ how can u exactly get that 
can u show me what u did?

vera_ewing · Answer

i just did 25.4-23.3

somy · Answer

lol thats just temperature = Delta T 
you havent used the formula

vera_ewing · Answer

oh wait so then what do i do?

somy · Answer

lel try reading what i said earlier :3

somy · Answer

m= mass of water 50g
c= specific heat of water = 4.18 J/°C g 
Delta T is temperature change = 25.4°C - 22.3°C = 3.1°C
so use all the values and put them into the formula 
Q= mc Delta T

vera_ewing · Answer

hmm ok well i'm not really sure how to do it. can you just do it and explain the steps to me?

somy · Answer

and you will get the value for Q 
and we are not done there yet

somy · Answer

$$\sf Q = m \times c \times \Delta T$$
$\sf \Delta T$, that triangle is sign of Delta and means 'change', in other words change in temperature

somy · Answer

i gave u all the values above so put them into the formula 
its just multiplication, im sure you can do it :3

somy · Answer

write the value you get 
then we'll move on to second step