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Use the following information to compute the following (Integrals)
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\[\int\limits_{-1}^{1}f(x) = 6, \int\limits_{1}^{4}f(x) = -2. \int\limits_{-1}^{1}h(x)=9\] Find \[\int\limits_{4}^{1}6f(x)dx\]
well I can move the 6 to the font
not sure were to go from there.
where*
Is that h(x), or f(x).
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in the given information there is one h(x)
I am honestly stumped by this. I think, it is given \[\int\limits_{1}^{4?}f(x)=9\] So, 6*\[\int\limits_{4}^{1}f(x)\]=6*-9=-45... But, I think this is a horrid solution.
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