Draw the product of the following reaction between propanoyl chloride and p-methoxynitrobenzene. Include all formal charges. (Image attached below.)

Question

anonymous · Answer

attachment

thadyoung · Answer

Here's a hint: first you have the lewis acid reacting with the propanoyl chloride to give you:
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You now have a great electrophile, which can undergo a reaction with the p-methoxynitrobenzene.

thadyoung · Answer

Think about where the electrophile would prefer to attack to give you the product.

academicgurusinc · Answer

The overall reaction is: $$Propanoyl Chloride + p-methoxy nitrobenzene \rightarrow 2-methoxy-5-nitro-1-propanoyl benzene + HCl$$ the complete mechanism is attached in the form of picture but in the picture, methyl group is attached on para postion which is ortho, para directing by inductive effect while the methoxy group is ortho para directing by resonance effect. the overall mechanism just changes replacement of CH3 by OCH3 and the rest is same. I hope that helps. If you found this helpful, I encourage you to subscribe to our youtube channel ( https://www.youtube.com/channel/UCYiI7SmkU4_vhdSzKBWsifg), to stay current with all of our new videos. Regards, Academic Gurus Inc. Twitter (Academic_Gurus) Facebook (AcademicGurusInc) Youtube (Academic Gurus Inc)

thadyoung · Answer

Why don't you help rather than give the answer.