Find the area of the trapezoid and leave your answer in simplest radical form
Here is the pic
Help plz
use sine and cosine to find the dimensions of the triangle.. then you can find the area of the triangle and the rectangle and add them together.
But how do you use sine and cosine? You use it for triangle?
what mathematics class is this for?
Geometry
have you learnt the unit circle?
Ya it has been a long time
You would use the functions sine and cosine with 60 degrees to find the rest of the dimensions.
You mean press sin than (8)60
perhaps you learned about 30-60-90 triangles? the side opposite the 30 degree angle (i.e. the "short" leg) is 1/2 the hypotenuse and the other leg opposite the 60 degree angles is sqr(3) * h/2 (where h is the hypotenuse=8 in your problem)
But how do you put that in calculator
@phi
they say " leave your answer in simplest radical form" so they don't expect you to use a calculator. the height of the triangle is \[\frac{8 \sqrt{3}}{2} = 4 \sqrt{3} \]
Ok and don't you find area of rectangle?
@phi
you could find the area of the rectangle and of the small triangle and add them up or you could find the area of the trapezoid = (top+bottom)/2 * height to finish this problem, you need to find the "short leg" of the 30-60-90 triangle. it is hypotenuse/2
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