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Mathematics 8 Online
OpenStudy (janu16):

Find the area of the trapezoid and leave your answer in simplest radical form

OpenStudy (janu16):

Here is the pic

OpenStudy (janu16):

Help plz

OpenStudy (anonymous):

use sine and cosine to find the dimensions of the triangle.. then you can find the area of the triangle and the rectangle and add them together.

OpenStudy (janu16):

But how do you use sine and cosine? You use it for triangle?

OpenStudy (anonymous):

what mathematics class is this for?

OpenStudy (janu16):

Geometry

OpenStudy (anonymous):

have you learnt the unit circle?

OpenStudy (janu16):

Ya it has been a long time

OpenStudy (anonymous):

You would use the functions sine and cosine with 60 degrees to find the rest of the dimensions.

OpenStudy (janu16):

You mean press sin than (8)60

OpenStudy (phi):

perhaps you learned about 30-60-90 triangles? the side opposite the 30 degree angle (i.e. the "short" leg) is 1/2 the hypotenuse and the other leg opposite the 60 degree angles is sqr(3) * h/2 (where h is the hypotenuse=8 in your problem)

OpenStudy (janu16):

But how do you put that in calculator

OpenStudy (janu16):

@phi

OpenStudy (phi):

they say " leave your answer in simplest radical form" so they don't expect you to use a calculator. the height of the triangle is \[\frac{8 \sqrt{3}}{2} = 4 \sqrt{3} \]

OpenStudy (janu16):

Ok and don't you find area of rectangle?

OpenStudy (janu16):

@phi

OpenStudy (phi):

you could find the area of the rectangle and of the small triangle and add them up or you could find the area of the trapezoid = (top+bottom)/2 * height to finish this problem, you need to find the "short leg" of the 30-60-90 triangle. it is hypotenuse/2

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