need help with Level D and E!!!! Will give medal! http://www.insidemathematics.org/assets/problems-of-the-month/growing%20staircases.pdf
The problem basically follows the n+n*2+n*3...where n is the total no of steps, and 1, 2, 3... indicate the current step.
Level D and E are similar.
That doesn't really work for D and E.
Using that, take n common So, n(1+2+3...) 1+2+3... is an AP with the solution n(n+1)/2 So the total blocks = n*n(n+1)/2 The blocks for constructing the nth step is n^2.
I am talking about level D and E,not A, B, and C
that only works for level A, B and C.
I answered for level D and E.
you answered how many blocks make up the first level(the base) of a staircase with n steps?
i'm looking for a rule or an function that helps me determine how many blocks in all are needed for the n steps.
i need a general formula for the whole thing, not only for the base
@kutabs is correct. general formula for level D and E you can use is \(\dfrac{n^2(n+1)}{2}\)
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