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Mathematics 16 Online
OpenStudy (anonymous):

need help with Level D and E!!!! Will give medal! http://www.insidemathematics.org/assets/problems-of-the-month/growing%20staircases.pdf

OpenStudy (anonymous):

The problem basically follows the n+n*2+n*3...where n is the total no of steps, and 1, 2, 3... indicate the current step.

OpenStudy (anonymous):

Level D and E are similar.

OpenStudy (anonymous):

That doesn't really work for D and E.

OpenStudy (anonymous):

Using that, take n common So, n(1+2+3...) 1+2+3... is an AP with the solution n(n+1)/2 So the total blocks = n*n(n+1)/2 The blocks for constructing the nth step is n^2.

OpenStudy (anonymous):

I am talking about level D and E,not A, B, and C

OpenStudy (anonymous):

that only works for level A, B and C.

OpenStudy (anonymous):

I answered for level D and E.

OpenStudy (anonymous):

you answered how many blocks make up the first level(the base) of a staircase with n steps?

OpenStudy (anonymous):

i'm looking for a rule or an function that helps me determine how many blocks in all are needed for the n steps.

OpenStudy (anonymous):

i need a general formula for the whole thing, not only for the base

OpenStudy (anonymous):

@kutabs is correct. general formula for level D and E you can use is \(\dfrac{n^2(n+1)}{2}\)

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