H2(g) + I2(g) = 2HI(g)
The delta G for the reaction is 2.60 kj/mol at 25 degrees C. The initial pressures are
P H2 = 3.34 atm, P I2 = 0.024 atm and P HI = 0.24 atm.
What is the delta G for the reaction in kj/mol?

Question

H2(g) + I2(g) = 2HI(g)
 The delta G for the reaction is 2.60 kj/mol at 25 degrees C.  The initial pressures are 
 P H2 = 3.34 atm, P I2 = 0.024 atm and P HI = 0.24 atm.
 What is the delta G for the reaction in kj/mol?

perl · Answer

Is there a formula we can use , from your notes or class.

dedi · Answer

okay are there any answer choices?

dedi · Answer

Well I think it's 1.78kJ/mol for the delta G

dedi · Answer

that should be the answer hello?

anonymous · Answer

the formula is delta G= delta G degree + RT lnQ
R=8.314 j/mol-k
q=Keq