subtract -5b-y/6b -8b+7y/6b simplify your answer as much as possible
@jdoe0001
\(\bf -\cfrac{5b-y}{6b}-\cfrac{8b+7y}{6b}\quad or\quad \cfrac{-5b-y}{6b}-\cfrac{8b+7y}{6b}\quad ?\)
if the sign is in "front of the fraction", then is multiplying it if not, then is not, it simply belongs to a term only as opposed to affecting all other terms
so, is the negative, in front of the fraction, or just part of -5b?
its front of the fraction
k
how do I solve it?
\(\bf -\cfrac{5b-y}{6b}-\cfrac{8b+7y}{6b}\implies \cfrac{-5b+y}{6b}-\cfrac{8b+7y}{6b} \\ \quad \\ \cfrac{-5b+y-(8b+7y)}{6b}\impliedby LCD\textit{ is 6b, since is the same for both} \\ \quad \\ \cfrac{-5b+y-(8b+7y)}{6b}\implies \cfrac{-5b+y-8b-7y}{6b}\)
what do I do now?
subtract in the numerator what you can and from whatever is left see if you can cancel out anything with the denominator
-7b+y-7y/b?
hmmm.... something tells me the negative sign is not the proper place can you post a quick screenshot of it? use the blue button that says [Attach File]
it is in the right spot its in front of the problem
well -5b-8b = -13b +y-7y = -6y so the top gives then -13b-6y and the denominator is 6b no common factors atop and below there
but if the 8b or the 5b were of a different sign... there could be one, thus I'd think the signs might be off, thus a screenshot may clarify that
the - sign is not apart of the numbers its totally separate its in front of the fractions
ok... then those are the values then \(\bf \cfrac{-5b+y-(8b+7y)}{6b}\implies \cfrac{-5b+y-8b-7y}{6b}\implies \cfrac{-13b-6y}{6b}\)
and now I cancel them out like -13-y?
-y? is -6y well.. you can't simplify it further
like 13b -6y/6b wouldn't you cancel the 2 6's and the b and be left with -13 -y?
nope, if you have a + or - sign, no dice only time you can do it, is when they're factors, or they have a * in between that is, they're multiplying
reason why I think the signs migh be off a quick screenshot might show a bit more
I cant screenshot but how do I get the answer?
well...that is the answer \(\bf \cfrac{-5b+y-(8b+7y)}{6b}\implies \cfrac{-5b+y-8b-7y}{6b}\implies \cfrac{-13b-6y}{6b}\)
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