What polynomial has roots of -4, 1, and 6?
x3 - 3x2 - 22x + 24 x3 - x2 - 26x - 24 x3 + x2 - 26x + 24 x3 + 3x2 + 14x - 24
cna someone help me out?
Hey! :D
Hey :)
Okay so for example: (x-4)(x+5)=0 has roots x=4, -5
You set x-4=0 and solve for x you see
So if you know those are the roots, how can you apply this information to solve your question?
lemme think hold on a sec
No problem!
Hint: what are the roots of (x+4)(x-1) ?
\(\large { x=\{-4,1,6\}\implies \begin{cases} x=-4\to x+4=0\to &(x+4)=0\\ x=1\to x-1=0\to &(x-1)=0\\ x=6\to x-6=0\to &(x-6)=0 \end{cases} \\ \quad \\ (x+4)(x-1)(x-6)=\textit{original polynomial} }\)
the roots of that are 4,-1?
would it be a?
hmm dunno... multiply them all three, see what you get
I get 24
24? and the "x" went MIA then
sorry is it x=24?
ahemm.. you're meant to multiply the binomials then those will give you the original polynomial thus multiply away :)
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