Question

Find two integers whose product is 136 such that one of the integers is one more than twice the other integer.

Answer 1

Let integers be x and y.
So we know the product = 136
So x*y = 136
Then we know ONE of the integers is ONE MORE than TWICE the other integer so let's say:
x = 2y + 1
Now substitute x = 2y + 1 into "x * y= 136"

Answer 2

Ok, I did that and I got \[2y ^{2}+1y-136=0\]

Answer 3

I tried to do the diamond method but I couldn't get an answer

Answer 4

yep now we want to solve for y so you're going to have to change that into the form
(2y ) (y ) = 0

Answer 5

alright let's think of two numbers that multiply to give you 136.
Hint: i'd use 17 and 8