I do not where to put this question: if vo= 10V at 30° C, in the circuit(please click/tap link) shown below, find it at 15° C and 65° C.
The current through the diode is a function of temperature: $$ \large{ I=I_0\left (e^{qV\over kT}-1\right) } $$ see - http://www.pveducation.org/pvcdrom/pn-junction/diode-equation Do you know the forward turn on voltage for diode 1N4148? If you do, then you should be able to calculate the voltage \(I_0\) and then find the current for any temperature T. Caution, T is in Kelvin. Once you know \(I_0\) you can then determine \(V_0\)
please ignore the diode 1N4148...., and change vo= -8V at 30degC my friend, and my prof did this: \(\sf \large \frac{v_o'}{v_o}=\frac{I_R'}{I_R}\\65°\\I_R'=2^{\frac{65-30}{10}}I_R\\ \hspace{10pt}=11.3I_r\) \(\sf \large \frac{ v _{o}-(-10) }{ { v '_{o}-(-10) }}=\frac{ 11.3 i _{R} }{ i _{R} }\\ \large \frac{v_o'+1c}{-8 + 10}=11.3\\v_o' + 10 =(11.3)(2)\\v_o' = 12.6V\)
I did not get how to do this...
So the diode is NOT in the circuit?
it is, but I it will be in reverse biased
@Hero
physics :)
lol... my math is physics right now, my electronic circuits course is like my math, adn physics.I do not know where to put it.
yep "find more subject" button is not working http://openstudy.com/study#/groups/Physics here is aa link if you want to post it there or new question :) thanks:)
Thanks
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