Help pleeasee(:
Determine which of the following statements is true concerning the values described in column #1 and column #2. The value found in column #1 is greater than the value found in column #2. The value found in column #1 is less than the value found in column #2. The value found in column #1 is equivalent to the value found in column #2. The relationship between column #1 and column #2 cannot be determined by the information given.
Column 1-The x-coordinate of the vertex of the equation y = 2x2 − 4x + 12 Column 2- The x-coordinate of the vertex of the equation y = 4x2 + 8x + 3
The one for column 1 is suppose to be 2x^2-4x+12
@jim_thompson5910 @Nnesha @nincompoop @sleepyjess
The vertex is found when y'=0 . So for column 1 y'=4x-4=0 . Then x=(4/4)=1 . Similarly you can solve for column 2, and you will get your answer.
use this formula to find vertex formula \[\huge\rm \frac{ -b }{ 2a }\]
quadratic equation \[\huge\rm Ax^2 + Bx + C= 0\]
y = 2x2 − 4x + 12 what is a and b in this quadratic equation ?
refresh!! if there are diamonds(question marks)
I have no idea :/
quadratic equation \[\huge\rm Ax^2 + Bx + C= 0\] number at front of x^2 is a and a number at front of x is b
y = 2x2 − 4x + 12 what is a and b in this quadratic equation ? same with this one
Oh i see, Sorry I didnt see you post it the first time. A would be 2 and b would be -4
yes right so plug that into the formula \[\huge\rm \frac{ -b }{ 2a }\]
would the negative four stay negative?
b is negative and there is another negative in the formula so - times -4 = ?
positive
yes right so what is final answer
\[\frac{ 4 }{ 4}\]
looks good
so 1
yep right now do same thing with 2nd Column use same formula substitute b and a into it and solve
\[\frac{ 8 }{ 8 }\]
once again 1
so it would be C?
nope that not suppose to be one
Gah.
|dw:1425797351804:dw| remeber there is negative sign and b is positive this tiem
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