What is the volume occupied by 3.00 moles of nitrogen gas (n2) at STP?

Question

dtan5457 · Answer

So I believe you have to do the ideal gas law.

p=1atm
v=???
t=273k
r=0.0821 (molar gas constant)
n=3

so in this case..I would think it would be 

v x 3=273(0.0821)(1atm)

I get v=7.47 liters

but my book says its 67.2

what did i do wrong?

dtan5457 · Answer

@aaronq

dtan5457 · Answer

@Kainui @Abhisar

anonymous · Answer

You simply use the rule aside from Avogadros Contant, in which 1mol of a substance = 22.4litres . What your equation is is 3mol=x. Then x=3*22.4/1=67.2litres. 
Got it?

dtan5457 · Answer

wow never mind....forgot to do some reading on my book. standard mole has 22.4 L as the volume...i just multiply by 3 here.