two equally charged particles held 3.20mm apart are released from rest the initial acceleration of the first prticle is observed to be 7.22 m/s^2 and that of the second be 9.16m/s^2 the mass of the first particle is 6.31*10^-7 kg find (a)mass of second particle? (b) the magnitude of the common charge?

Question

two equally charged particles held 3.20mm apart are released from rest the initial acceleration of the first prticle is observed to be 7.22 m/s^2 and that of the second be 9.16m/s^2 the mass of the first particle is 6.31*10^-7 kg  find (a)mass of second particle? (b) the magnitude of the common charge?

anonymous · Answer

@IrishBoy123  what formula should i use??

shamim · Answer

Let the charge
q1=q2=q

shamim · Answer

We can use 
F=ma
For first particle

irishboy123 · Answer

just use newton, net force on system (ie the 2 particles) = 0 as the forces are between the particles.

so F1 = m1a1, F2 = m2a2, F1 = F2, thus m1a1 = m2a2

i have not bothered with the signs, clearly they are moving in different directions, but the magnitudes of the forces should be equal.

shamim · Answer

Given
m=6.31*10^-7kg
a=7.22m/s

shamim · Answer

U hv to use coulomb's law to find out charges

anonymous · Answer

ok got it