Question

WILL GIVE MEDAL!!!!

A= (d1)(d2)/2
A=2a^2-8a
d1=(a-4)

Answer 1

what is the question?

Answer 2

SOLVE FOR D2

Answer 3

substitute your values in

A= (d1)(d2)/2
A=2a^2-8a
d1=(a-4)

since you know what A is and what d1 is

2a^2-8a= (d1)(d2)/2

then sub in d1

2a^2-8a= (a-4)(d2)/2

rearrange to get d2, can you do that?

Answer 4

i know the answer is 4a i just keep on
getting something different

Answer 5

4a^2 - 16a=(a-4)(d2)
(4a^2-16a)/(a-4)=d2

4a(a-4)/(a-4)=d2
a-4 will cancel out to be 1

4a(1)=d2
d2=4a

Answer 6

do you HAVE to factor (4a^2-16a)?

Answer 7

well because we have

(4a^2-16a)/(a-4)

you would first try to factorise the top to see if it can cancel anything out to make it simpler, or you can use division to get the answer

I would recommend factorising though since this question is basically asking for it

Answer 8

Oh okay Thank you I've been stuck on this problem for like half an hour.

Answer 9

good luck on your next question!

Answer 10

Thanks