Question

A student made the table shown below to prove that PQ is equal to RQ:Statements Justifications
SQ = TQ
Given
m∠SQP = m∠TQR
Given
m∠RSQ = m∠PTQ
Given
m∠SQR = m∠SQP + m∠PQR
Angle Addition Postulate
m∠TQP = m∠TQR + m∠PQR
Angle Addition Postulate
m∠TQP = m∠SQP + m∠PQR
Substitution
m∠SQR = m∠TQP
Transitive Property
PQ = RQ
CPCTC

Provide the missing statement and justification in the proof.
Using complete sentences, explain why the proof would not work without the missing step.

Answer 1

@ganeshie8

Answer 2

@sleepyjess

Answer 3

@Jaynator495

Answer 4

its ok

Answer 5

no need to appoligise

Answer 6

@ash2326 @ganeshie8 @jim_thompson5910

Answer 7

is my answer right or am i missing somthing?

Answer 8

anyone there

Answer 9

@sleepyjess

Answer 10

is any one here

Answer 11

@kirbykirby @freckles

Answer 12

am i close Nnesha

Answer 13

i guess yes but i don't know how PQ=RQ by sas

Answer 14

do you knew if this question has ever been asked before

Answer 15

where is your answer ??
did you delete that ?? :O

Answer 16

@phi @Michele_Laino

Answer 17

which statement is missing ?

the steps all look good until the very last step.
There is no step that shows which two triangles are proven to be congruent.
notice , though, that you have
angle PQT (= angle SQR)
side QT (= side QS)
angle PTQ (= angle RSQ)

that means you can claim triangle PQT is congruent to triangle RQS
and now you can make the last statement
PQ= RQ by Corresponding parts of congruent triangles