Indicate the equation of the given line in standard form. The line that contains the point Q( 1, -2) and is parallel to the line whose equation is... y - 4 = 2/3 (x - 3) Anyone know how to solve this??
what do you know about the sloeps of parallel lines?
slopes*
aren't they the same?
correct. and so the slope of our line is the same slope as the given line
So, it is 2/3 ?
correct. now since we'd have to use point-slope form, we need one other piece of information \(y-y_1=m(x-x_1)\)
I'm not sure what it is.
(x1,y1) is the point the line goes through m is the slope of the line
we found m
oh, so (1,-2) ?
correct. \(y-y_1=\dfrac{2}{3}(x-x_1)\)
so, the equation would look like this? -2-4= 2/3 (1-3)
oh no, we're only replacing x1 and y1
the only information we needed from the other equation was the slope
\((x_1,y_1) = Q( 1, -2) \) m=2/3
okay, i'm lost again. haha so how do we solve that?
lemme try some color coding
\(y-\color{red}{y_1}=\color{pink}m(x-\color{blue}{x_1})\) \(y - 4 = \color{pink}{\dfrac{2}{3}}(x - 3)\) passes through point \(Q( \color{blue}{1}, \color{red}{-2}) \)
It makes some sense but i'm not sure how to solve it now
you just plug and simplify into y=mx+b form pretend it's one of those kindergarten toys where the red shape goes in the red hole
y- (-2)= 2/3 (x-1) ?
yeah. start with the left hand side simplify y--2
I got y= 2/3x-8/3 when I put it into standard form I got 2x-3y= 8 Which fits into my answer box online
why'd you put it in standard form?
that's what the question said to do
oh I didn't read the first line, give me a moment
it said I got it right so thank you! you helped me pass (:
y- (-2)= 2/3 (x-1) ? y+2=2/3x-2/3, subtract 6/3 (2) from both sides y=2/3x-8/3
awesome
i just googled how to convert to standard form for completion's sake y=2/3x-8/3 3y=3(2/3x-8/3) 3y=2x-8 2x-3y=8 good job
Thank you! and thanks for the help also
anytime, yo. tag me in the future if it takes a while to get an answer
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