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Mathematics 13 Online
OpenStudy (anonymous):

Please will someone talk through this?

OpenStudy (anonymous):

talk through what?

OpenStudy (anonymous):

Adding the questions now :)

OpenStudy (anonymous):

oh ok sorry for interrupting

OpenStudy (anonymous):

|dw:1425848475996:dw|

OpenStudy (anonymous):

i don't get it.

OpenStudy (anonymous):

Figure 2 shows the curve with the equation y^2 = 9(x-1) and the line with the equation 3x+y=9

OpenStudy (anonymous):

The curve crosses the x-axis at point A, and the line intersects the curve at the points P and Q (a) Find the coordinates of point A (b) Find, using algebra, the coordinates of P and Q

OpenStudy (anonymous):

So far I got that, y^2 = 9x-9 so y=3x-3

OpenStudy (asnaseer):

HINT: to find point A, you know that along the x-axes we have y=0, so solve:\[y^2=0=9(x-1)\]

OpenStudy (anonymous):

OpenStudy (anonymous):

there is a graph...

OpenStudy (anonymous):

The one I drew isn't accurate, just a sketch

OpenStudy (asnaseer):

@Green101 - use the hint I gave to solve part a)

OpenStudy (anonymous):

I got a = (1,0) and I know thanks!!

OpenStudy (anonymous):

It is mainly part B I don't understand!!

OpenStudy (asnaseer):

great! now for part (b) you know that along the line we have:\[3x+y=9\]\[\therefore y=9-3x\]\[\therefore y^2=(9-3x)^2=81-54x+9x^2\]

OpenStudy (asnaseer):

and we know that along the curve we have:\[y^2=9(x-1)=9x-9\]these two equations must be equal at points P and Q

OpenStudy (asnaseer):

therefore you need to solve:\[81-54x+9x^2=9x-9\]

OpenStudy (asnaseer):

you should be able to rearrange this into a standard quadratic equation in \(x\) and then factor it and solve

OpenStudy (anonymous):

You are an absolute legend! Thank you so so much! If I post the answer here will you check it??

OpenStudy (asnaseer):

sure - and thank you very much for the compliment :)

OpenStudy (anonymous):

So far I got that \[x = 5, 2 \]

OpenStudy (asnaseer):

perfect! :)

OpenStudy (anonymous):

from \[x^2-7x+10=0\]

OpenStudy (anonymous):

So what would I do from here to calculate P and Q?

OpenStudy (asnaseer):

simplest is to use the equation of the straight line for each x to get the corresponding y value

OpenStudy (anonymous):

So, finally I got

OpenStudy (anonymous):

\[y=(-3)(5)+9 \] \[\therefore y=6 < 0 \] and therefore Q = (5, -6)

OpenStudy (asnaseer):

correct co-ordinates for Q but I believe you meant to pu:\[y=-6\lt0\]

OpenStudy (asnaseer):

*put

OpenStudy (anonymous):

\[y=(-3)(2)+9 \]\[\therefore y=3 > 0\] and so p = (2,3)

OpenStudy (anonymous):

And yeah I did XD

OpenStudy (asnaseer):

you have the right answers :)

OpenStudy (anonymous):

Yay! Again thank you so much!! Really needed someone to talk through all this!

OpenStudy (asnaseer):

yw :)

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