In the reaction, Cu + 2AgNO3 -- Cu(NO3)2 + 2Ag, 12.7 g Cu produced 38.1 Ag. Which one is percent yield of silver? a) 29.4% b)56.7% c)77.3% d)88.2% e)176%

Question

In the reaction, Cu + 2AgNO3 --> Cu(NO3)2 + 2Ag, 12.7 g Cu produced 38.1 Ag.  Which one is percent yield of silver? a) 29.4% b)56.7% c)77.3% d)88.2% e)176%

matt101 · Answer

In questions like this, always convert to moles. How many moles of Cu and Ag are there?

jfraser · Answer

you need to use the 12.7g of Cu as your starting point and find out how many grams of silver $should \space have \space been$ produced, then compare that to the amount that is $actually$ produced to find your percent yield