Question

Trig exact value on interval [0,2pi)

Answer 1

tan^-1 sqrt3/3

Answer 2

I'd think you'd just use the calculator for that one
same as you'd on the last one as well

Answer 3

Don't allow us to use one. My main thing is determine what quadrants to use.

Answer 4

I assume you have a Unit Circle with values of common angles? at least with the cosine and sine, right?

Answer 5

Yes I do.

Answer 6

bear in mind that that \(\bf tan^{-1}\left( \cfrac{\sqrt{3}}{3} \right)=\theta\qquad tan(\theta)=\cfrac{\sqrt{3}}{3}\leftarrow \cfrac{sin(\theta)}{cos(\theta)}
\\ \quad \\
also\qquad \cfrac{sin(\theta)}{cos(\theta)}\to \cfrac{1}{\sqrt{3}}\implies \cfrac{1}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{\sqrt{3}}{3}\)

Answer 7

so.. whatever sine/cosine were, their division ended up as \(\bf \cfrac{1}{\sqrt{3}}\)

Answer 8

that usually means that the cosine is the one with the radical
the one I can see right off is \(\bf \cfrac{\pi }{6}\)

Answer 9

Alright I think I'm getting it now. Thank you so much for the help!