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Mathematics 19 Online
OpenStudy (anonymous):

A bacteria culture grows exponentially. After 2 hours there are 600 bacteria and after 8 hours there are 75000 bacteria. (A) Find the culture's initial population (B) When will the population reach 200,000?

OpenStudy (anonymous):

(a) 120 bacteria (b) 9.219 hours For (a), how can you find the initial population when you have two different unknown variables?

OpenStudy (anonymous):

you can start counting at any time you like k

OpenStudy (anonymous):

you can start at hour 2 and call that hour zero then to find the initial amount, once you have your model, put \(t=-2\)

OpenStudy (anonymous):

Oh, I see! Would I still start from 2 hours and call it zero for (B)?

OpenStudy (anonymous):

really makes no difference "when" is time, so you can say whatever hours after hour 2, or whatever hours plus 2 after hour zero did you get a model for this?

OpenStudy (anonymous):

75000=600xe^8k?

OpenStudy (anonymous):

oh you want to solve it that way

OpenStudy (anonymous):

that will work, but it is only 6 hours from hour 2 to hour 8, so you should solve \[75000=600e^{6k}\] for \(k\)

OpenStudy (anonymous):

Oh, ok, thanks!

OpenStudy (anonymous):

you should get \[k=\frac{\ln(5)}{2}\] or \[k=.80472\] making your model \[P(t)=600e^{.80472t}\]

OpenStudy (anonymous):

then if you want the initial amount, put \(t=-2\)

OpenStudy (anonymous):

you do in fact get 120 exactly

OpenStudy (anonymous):

there is an easier way to do this, but that is ok, one way is good enough

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