Question

Use the quadratic formula to find the complex roots (Leave answer in simplest a+bi form) :

3x²-2x+1=0

Answer 1

deja vu
that strange feeling you get when you think you've been there before

Answer 2

didn't we just do this and get
\[\frac{1\pm\sqrt{2}i}{2}\]

Answer 3

Sorry, I had the question wrong

Answer 4

if you want to make it look like \(a+bi\) split it up as
\[\frac{1}{2}+\frac{\sqrt{2}}{2}i\]

Answer 5

is that the simplest a+bi form?

Answer 6

oh

Answer 7

yes

Answer 8

but, I was curious why 2 isnt multiplied by 3 on the denominator

Answer 9

\[\frac{ 2\pm \sqrt{-8} }{ 2(3) }\]

Answer 10

a=3 b=-2 c=1

x=[-b +- sqrt(b^2 -4*a*c)] / 2*a

x= [--2 +- sqrt(4 - 4*3*1)]/ 6

x = [2 +- sqrt(4 -12)]/6

x = [2 +- sqrt(8)] / 6

Answer 11

can I convert to a+bi form