Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

What does the number outside a venn diagram but inside the rectangle mean?

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

it means it is in the "universal set" but not in the set labelled in the venn diagram you got an example?

OpenStudy (anonymous):

http://gyazo.com/6a125510f0341a80d062c9f95f05bd96

OpenStudy (misty1212):

btw the whole set up is the "venn diagram" not just the circles

OpenStudy (misty1212):

that means than (i guess, there are no words involved) that 7 people have no sisters or brothers they are just lonely only children

OpenStudy (misty1212):

the way i interpret it is that 10 have sisters and brothers, 5 have brothers only 8 have sisters only and 7 have neither brothers or sisters

OpenStudy (anonymous):

given the venn diagram what is the probability that a person is an only child or only has sisters?

OpenStudy (anonymous):

@misty1212

OpenStudy (misty1212):

so the 7 is the only children right?

OpenStudy (anonymous):

Im guessing so?

OpenStudy (misty1212):

yea, and how many have only sisters?

OpenStudy (anonymous):

8

OpenStudy (misty1212):

for a total of how many only child or sister only? i.e. what is \(7+8\)?

OpenStudy (anonymous):

15

OpenStudy (misty1212):

ok that will go in the top of our fraction now how many people are there total (add up all the numbers)

OpenStudy (anonymous):

30

OpenStudy (misty1212):

k good so \[\frac{15}{30}\]but reduce that

OpenStudy (anonymous):

http://gyazo.com/0c7ac34dde63abe6c03b35bc7c17363d @misty1212 Is that right?

OpenStudy (misty1212):

you need to do \[2\times 3\times 4\]

OpenStudy (anonymous):

24 sweet

OpenStudy (misty1212):

yeah always pick C

OpenStudy (anonymous):

http://gyazo.com/fc86588ccf196ef23d4d0084b52a9de3 @misty1212

OpenStudy (misty1212):

two out of 3 or i guess \(.67\) rounded

OpenStudy (anonymous):

http://gyazo.com/29cb0b746bdfa7ac4469b45477065075

OpenStudy (anonymous):

@misty1212

OpenStudy (misty1212):

how many like art total?

OpenStudy (anonymous):

13

OpenStudy (misty1212):

hmm no

OpenStudy (anonymous):

7 then

OpenStudy (misty1212):

lol

OpenStudy (misty1212):

add up all the numbers in the art circle there are three of them

OpenStudy (anonymous):

17

OpenStudy (misty1212):

ok whew

OpenStudy (misty1212):

of those 17, how many are also in the circle labeled music?

OpenStudy (anonymous):

10

OpenStudy (misty1212):

ok so \[\frac{10}{17}\] is your answer

OpenStudy (anonymous):

You are awesome.

OpenStudy (misty1212):

\[\color\magenta\heartsuit\]

OpenStudy (anonymous):

http://gyazo.com/bd01f8bc81ed2a8b780b4551178fab29

OpenStudy (misty1212):

the middle path only goes to the pumpkin, no where else so it is certain the certain event has probability 1

OpenStudy (anonymous):

Thats the answer?

OpenStudy (misty1212):

no i am trying to trick you

OpenStudy (misty1212):

jk yes, that is the answer!

OpenStudy (misty1212):

some sort of on line probability class? or just on line homework?

OpenStudy (anonymous):

http://gyazo.com/67ff70b4a09755ebba2ef9d6040eaf99

OpenStudy (anonymous):

Online course (I just came from work and my brain is dry atm. I know how to do most of this I just dont want to get something I know wrong.

OpenStudy (anonymous):

Is it 1/3?

OpenStudy (misty1212):

lol this one would be harder but they have given you all the numbers you need, but it is not \(\frac{1}{3}\)

OpenStudy (anonymous):

Oh wait 2/3?

OpenStudy (misty1212):

add up all the numbers by the pumpkins

OpenStudy (mathstudent55):

Add the probabilities of pumpkins.

OpenStudy (mathstudent55):

Correct.

OpenStudy (misty1212):

yes it is \(\frac{2}{3}\) when you add them

OpenStudy (anonymous):

http://gyazo.com/aa99a22f5098d9577e06b92fd066cefe is it 1/7 = .14?

OpenStudy (anonymous):

@misty1212

OpenStudy (misty1212):

how you gonna get two greens?

OpenStudy (anonymous):

Wait I'm lost. There is only one green.

OpenStudy (misty1212):

right so how can you get two?

OpenStudy (anonymous):

By rollling twice?

OpenStudy (misty1212):

that just means it is impossible i hope one of the choices is zero

OpenStudy (misty1212):

by rolling twice lol yeah or by reaching in and picking out the green, then doing it again no, the answer is you cannot, so the probability is zero

OpenStudy (anonymous):

It's a fill in the blank this is what I put: If your only allowed to role each of the jars once, you can only get green once, therefore making it impossible to get two green.

OpenStudy (misty1212):

looks good to me where do you work?

OpenStudy (anonymous):

Publix

OpenStudy (misty1212):

i guess i asked, didn't i?

OpenStudy (anonymous):

Wait what? lol

OpenStudy (misty1212):

ooh it is a grocer in NC?

OpenStudy (misty1212):

all over the south i see

OpenStudy (anonymous):

Yes it is a grocery in the south. :P http://gyazo.com/54c7c708ce725f0361502280560d56de Last one

OpenStudy (misty1212):

i would guess \(.27\) because the other one is a motorcycle accident

OpenStudy (anonymous):

Thats not one of the choices.

OpenStudy (misty1212):

ok then try \[.65\times .27\]

OpenStudy (anonymous):

it's .25 you have to add all accidents and divide by 4. = 1/4 = .25

OpenStudy (misty1212):

i disagree

OpenStudy (anonymous):

That was one of the choices, oh well I submitted my work lol

OpenStudy (misty1212):

you are already male with probability \(.65\) you own a car, and if so with probability \(.27\) you get in an accident so it should be\(.65\times .27=.1755\)

OpenStudy (misty1212):

good luck, sure yo udid ok

OpenStudy (anonymous):

WAIT flutter you're right.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!