Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Complete the equation of the graphed linear function in point-slope form. y – (–2) = (x – ) http://static.k12.com/calms_media/media/1522000_1522500/1522154/1/b46c3a188a94fdd3b92220d260520511848f250c/MS_IMC-140829-100656.jpg

OpenStudy (anonymous):

@shawmoes

pooja195 (pooja195):

what are the coordinates? that the dot is on?

pooja195 (pooja195):

when you figure those out you should be able to put it in the equation

OpenStudy (anonymous):

1,-2

OpenStudy (anonymous):

I don't really understand

OpenStudy (anonymous):

So (1,-2) is where the dot is at right? So the 1 is the x1 value and -2 is the y1 value. So we simply put these numbers into the equation (y-y1)=m(x-x1) . Just plug them in, what do you get?

OpenStudy (anonymous):

first blank is 1 second is -2?

OpenStudy (anonymous):

@shawmoes

OpenStudy (anonymous):

The first blank is already filled in as -2, what's the second blank?

OpenStudy (anonymous):

Remember that your equation has the slope m , which we still have to find. For now what is our x1 value?

OpenStudy (anonymous):

I'm super lost sorry @shawmoes

OpenStudy (anonymous):

Please refer to http://www.mathsisfun.com/algebra/line-equation-point-slope.html . It might help you more :)

OpenStudy (anonymous):

@shawmoes could you please help me get the answer I've been working on this for a while

OpenStudy (anonymous):

OK if slope is rise divided by run, what is the slope here? |dw:1425869080064:dw|

OpenStudy (anonymous):

3?

OpenStudy (anonymous):

@shawmoes

OpenStudy (anonymous):

Yes that's right, so our equation is( y+2) = 3(x-1) .

OpenStudy (anonymous):

ugh still didn't pass well ty for help

OpenStudy (anonymous):

No problem, I am 100% sure that's the answer, so take it up with your teacher yes :) . Take care.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!