Question

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The table below shows the distance d(t) in feet that an object travels in t seconds:

What is the average rate of change of d(t) between 3 seconds, and 5 seconds and what does it represent?

Answer 1

Table:


t (second) d(t)(feet)
3 126
4 224
5 350
6 504

A. 59.5 ft/s; it represents the average speed of the object between 3 seconds and 5 seconds
B. 112 ft/s; it represents the average speed of the object between 3 seconds and 5 seconds
C. 112 ft/s; it represents the average distance traveled by the object between 3 seconds and 5 seconds
D. 59.5 ft/s; it represents the average distance traveled by the object between 3 seconds and 5 seconds

Answer 2

@Tootles143

Answer 3

So you need help with the unit rate?

Answer 4

Average rate of change actually :)

Answer 5

Oh ok

Answer 6

average rate of change = slope \[\huge\rm \frac{ y_2 - y_1 }{ x_2 -x_1 }\]formula to find slope
use point from 3 to 5 to find slope

Answer 7

first number in order pair is x and 2nd is y so \[\huge\rm (x_1 , y_1)(x_2 , y_2)\]

Answer 8

@Nnesha Gots it from here. ;)

Answer 9

okay :) thanks anyway tootles

Answer 10

So Neesha what would be the y2-y1 then?

Answer 11

Your welcome. I guess.

Answer 12

okay say all answer choices are from 3 to 5 seconds
use this number time is x and d is y