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Mathematics 14 Online
OpenStudy (anonymous):

Algebra 2???

OpenStudy (anonymous):

OpenStudy (micahm):

@iGreen

OpenStudy (igreen):

Find the slope first. Plug the two points into the slope formula. (-2, 2) (2, -2) \(m = \dfrac{-2-2}{2+2}\) Simplify

OpenStudy (anonymous):

-1

OpenStudy (anonymous):

how do I put it in y = mx + b form, and make b the constant?

OpenStudy (anonymous):

@iGreen ???

OpenStudy (adi3):

3 hours later no answer

OpenStudy (igreen):

You plug in the slope and one of the points into point-slope form first, then simplify. \(y - y_1 = m(x - x_1)\) Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope. So we have: \(y - 2 = -1(x + 2)\) Distribute -1 into the parenthesis: \(y -2 = -x - 2\) Add 2 to both sides, what's -2 + 2?

OpenStudy (adi3):

I take my words back

OpenStudy (igreen):

Lol

OpenStudy (adi3):

okay i get it

OpenStudy (anonymous):

0 lol

OpenStudy (adi3):

can someone medal me I did a lot of effort @iGreen or @Haleyy_Bugg

OpenStudy (igreen):

Yes, so we have: y = -x

OpenStudy (adi3):

I was kidding and actually someone medaled it who ever was it thank you

OpenStudy (igreen):

That was me..

OpenStudy (igreen):

Let me give 2 medals, hold on.

OpenStudy (igreen):

There, now everyone has at least 1 :P

OpenStudy (igreen):

Except micahm

OpenStudy (adi3):

thnx mate

OpenStudy (adi3):

@iGreen

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