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OpenStudy (anonymous):
OpenStudy (micahm):
@iGreen
OpenStudy (igreen):
Find the slope first.
Plug the two points into the slope formula.
(-2, 2) (2, -2)
\(m = \dfrac{-2-2}{2+2}\)
Simplify
OpenStudy (anonymous):
-1
OpenStudy (anonymous):
how do I put it in y = mx + b form, and make b the constant?
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OpenStudy (anonymous):
@iGreen ???
OpenStudy (adi3):
3 hours later no answer
OpenStudy (igreen):
You plug in the slope and one of the points into point-slope form first, then simplify.
\(y - y_1 = m(x - x_1)\)
Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope.
So we have:
\(y - 2 = -1(x + 2)\)
Distribute -1 into the parenthesis:
\(y -2 = -x - 2\)
Add 2 to both sides, what's -2 + 2?
OpenStudy (adi3):
I take my words back
OpenStudy (igreen):
Lol
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OpenStudy (adi3):
okay i get it
OpenStudy (anonymous):
0 lol
OpenStudy (adi3):
can someone medal me I did a lot of effort @iGreen or @Haleyy_Bugg
OpenStudy (igreen):
Yes, so we have:
y = -x
OpenStudy (adi3):
I was kidding and actually someone medaled it who ever was it thank you
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OpenStudy (igreen):
That was me..
OpenStudy (igreen):
Let me give 2 medals, hold on.
OpenStudy (igreen):
There, now everyone has at least 1 :P
OpenStudy (igreen):
Except micahm
OpenStudy (adi3):
thnx mate
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