What is the y-value for f(x) = cos(x) when x = -90°?
@demonchild99 @william.1233 @YGHOOTIE @dejmccray @haydenhd @Vendela
51
Put \(x=-90\)
\[f(x) = \cos(-90^{\circ})\]
And remember, cos(x) is an even function that means: \[\cos(-x) = \cos(x)\] It means negative angle just becomes positive..
so the answere will be? :D
\[f(x) = \cos(-90^{\circ}) \\ f(x) = \cos(90^{\circ})\] Find out what is cos(90), and f(x) is nothing by \(y-value\)..
*but
but? @eta?
ok never mind i see it now lol thank u so very much
but you only want answer, you do not want to learn the things.. :P
I wrote "nothing by y-value, there is no by, by should be but there..
never said that wat u told me actually help me figure out my last 5 questions i have
-.- not trying to be mean but please dont under dtimate people @eta
Hey, do I still need to mention that I was just kidding? I told my expression :P with that statement..
Okay, allow me to ask for sorry, I am sorry if you felt any bad from my side.. :(
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