The equation of the line of best fit of a scatter plot is y = 12x + 7. What is the slope of the equation? –12 –7 12 7
Pls Help I'm so confused
@AMYCARTER
what do you think?
I'm sorry. But I don't know this, I thought this was something different. Sorry, I tried.
I give medals pls help
@koolkat13
@GhastlyPack
@SolomonZelman
the slope is the value in front of the X so the slope is 12
but how do I FIND the answer
y = 12x + 7\(\large\color{slate}{ \\[0.6em] }\) \(\normalsize\color{slate}{ \bullet }\) when you plug in \(\normalsize\color{blue}{ 1 }\) instead of x, what do you get for y? \(\large\color{slate}{ \\[0.6em] }\) \(\normalsize\color{slate}{ \bullet }\) when you plug in \(\normalsize\color{blue}{ 2 }\) instead of x, what do you get for y? \(\large\color{slate}{ \\[0.6em] }\) \(\normalsize\color{slate}{ \bullet }\) when you plug in \(\normalsize\color{blue}{ 3 }\) instead of x, what do you get for y? \(\large\color{slate}{ \\[0.6em] }\) \(\normalsize\color{slate}{ \bullet }\) when you plug in \(\normalsize\color{blue}{ 4 }\) instead of x, what do you get for y? \(\large\color{slate}{ \\[0.6em] }\) answer these 4 questions for me.
ummm 12 * 1 = 12 + 7 = 19 right?
I will show you on the first question. \(\normalsize\color{black}{ y = 12x + 7 }\) \(\normalsize\color{black}{ y = 12\color{blue}{\cdot(1)} + 7 }\) \(\normalsize\color{black}{ y = 12 + 7 }\) \(\normalsize\color{black}{ y = 19 }\)
Can you find for me the y-value when we plug in \(\normalsize\color{blue}{ 2,~~3 }\) and \(\normalsize\color{blue}{ 4 }\) instead of x?
so i got the first question right
yes
i just didn't put it in the same format
so is 12 the right answer to my question?
Yes
ok
if you want to know why, bear with me..... (if not, then oh well... bye)
Do you want to know why ?
yes
okay, then (for now) please answer the remaining questions (the last 3 from the 4 questions) I asked.
so 2 instead of x 3 instead of x and 4 instead of x y= 12 * 2 + 7 = 12 * 2 24 24 + 7 = 31 y = 12 * 3 + 7 12 * 3 = 36 36 + 7 = 43 y = 12 * 4 + 7 12 * 4 = 48 48 + 7 = 55 so the answers are y = 31 y = 43 y = 55
so how was the answer 12
had to carry a massive TV to trash pickup sorry
Ok, see how every time you got 1 x unit up, the y value increases by 12 every time?
yeah
So, the value the y increases by is called the slope
Now, lets consider something abstract (lets make a theory)
\(\large\color{black}{ \displaystyle y={\rm \color{blue}{m}}x+{\rm \color{red}{b}} }\) \(\large\color{slate}{ \\[0.5em] }\) (this is a "y-intercept form"of a line.) \(\large\color{slate}{ \\[0.7em] }\) what happens when we plug in \(\large\color{black}{ \displaystyle {\rm \color{blue}{1}} }\) for \(\large\color{black}{ \displaystyle x }\) ? \(\large\color{slate}{ \\[0.5em] }\) \(\large\color{black}{ \displaystyle y={\rm \color{blue}{m}}x+{\rm \color{red}{b}} }\) \(\large\color{black}{ \displaystyle y={\rm \color{blue}{m}}\cdot(1)+{\rm \color{red}{b}} }\) \(\large\color{black}{ \displaystyle y={\rm \color{blue}{m}}+{\rm \color{red}{b}} }\) \(\large\color{slate}{ \\[0.7em] }\) what happens when we plug in \(\large\color{black}{ \displaystyle {\rm \color{blue}{2}} }\) for \(\large\color{black}{ \displaystyle x }\) ? \(\large\color{slate}{ \\[0.5em] }\) \(\large\color{black}{ \displaystyle y={\rm \color{blue}{m}}x+{\rm \color{red}{b}} }\) \(\large\color{black}{ \displaystyle y={\rm \color{blue}{m}}\cdot(2)+{\rm \color{red}{b}} }\) \(\large\color{black}{ \displaystyle y=2{\rm \color{blue}{m}}+{\rm \color{red}{b}} }\) \(\large\color{slate}{ \\[0.7em] }\) what happens when we plug in \(\large\color{black}{ \displaystyle {\rm \color{blue}{3}} }\) for \(\large\color{black}{ \displaystyle x }\) ? \(\large\color{slate}{ \\[0.5em] }\) \(\large\color{black}{ \displaystyle y={\rm \color{blue}{m}}x+{\rm \color{red}{b}} }\) \(\large\color{black}{ \displaystyle y={\rm \color{blue}{m}}\cdot(3)+{\rm \color{red}{b}} }\) \(\large\color{black}{ \displaystyle y=3{\rm \color{blue}{m}}+{\rm \color{red}{b}} }\) and on.....
So, for every 'x' we are adding 'm' once.
So this "m" is the slope.
it is the "rate of change"
that makes more sence thx
Join our real-time social learning platform and learn together with your friends!