Find the sum of a finite geometric sequence from n = 1 to n = 7, using the expression -4(6)^n-1 111,325 526 782 223,948
answer choices: 111,325 526 782 223,948
\(\large\color{black}{\displaystyle \sum_{ n=1 }^{ 7 } -4(6)^{n-1} }\) is that a good interpretation of the question ?
I guess..
you can apply the same formula
\(\large\color{black}{\displaystyle \Large\color{black}{ \displaystyle {\rm \LARGE S}_{_{n}}=\frac{a_{_{n}}\left(1-r^{n}\right)}{1-r}} }\)
what do I plug in for r?
as n=1, you are multiplying 0 times , times 6. as n=2, you are multiplying once times 6 as n=3, you are multiplying twice times 6 and on...
what is your common ratio ?
6
also, please go ahead and fix your answer choices:)
yes, r=6
what about n?
you want to find the sum of 7 terms (from n=1 to n=7)
so n is 7.
oh, in the formula I posted here, the a(n) was supposed to be a(1)
\(\bf\color{red}{\large\color{black}{\displaystyle \Large\color{black}{ \displaystyle {\rm \LARGE S}_{_{n}}=\frac{a_{_{1}}\left(1-r^{n}\right)}{1-r}} }}\)
ok thanks! can you please help me with one more problem?
\(\bf\color{black}{\displaystyle \Large\color{black}{ \displaystyle {\rm \LARGE S}_{_{n}}=\frac{(-4)\left(1-6^{7}\right)}{1-6}} }\)
what was your answer?
my answer was 223,948, am I right?
almsoy
how can you have a positive sum, when every term is negative ?
\(\rm\color{blue}{\href{http:///www.wolframalpha.com/input/?i=sum+from+1+to+7%2C+-4%286%29%5E%28n-1%29}{The~Sum~is....}}\) Also, I can verify it, by plugging the formula into the calculator \(\rm\color{green}{\href{http:///www.wolframalpha.com/input/?i=%28%28-4%29%C3%97%281-6%5E7%29%29%2F%281-6%29}{verification,~~by~~plugging~~in.}}\)
what answer did you get? (sorry I couldn't answer earlier, openstudy froze for some reason)
I got option D, but negative. The correct answer is -223,948
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