Question

http://prntscr.com/6eqr9g
HELP! WILL MEDAL AND FAN (especiallyifdirectanswer) :/

Answer 1

Always remember the rule of BEDMAS

Answer 2

What you first want to do is follow the rules of PEMDAS. You're going to want to do what's in the brackets first aka, these: []

Answer 3

http://www.symbolab.com/

Answer 4

So what should you do first?

Answer 5

I cant tell? theres the "(" in the middle?

Answer 6

B=Bracket
E=exponent
D=Divide
M= Multiply
A= Add
S= subtract

Answer 7

how would u even type this?? @TheEdwardsFamily

Answer 8

there's a [ in the middle of the ( you do the brackets first. Which are these [

Answer 9

@gardenGnostic follow that rule. Remember bracket is first. If you remember that rule. I grantee 10 years later you won't forget

Answer 10

http://prntscr.com/6eqtz3

Answer 11

-6?

Answer 12

Brackets, Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. That's the order you do things in. Yep, -6.

Answer 13

Now since the 5 is right beside the -6, what do you do?

Answer 14

uhh multiply?

Answer 15

Right-o!

Answer 16

:D

Answer 17

@gardenGnostic

Answer 18

wait hold on is the answer for the whole thing -4?

Answer 19

The rule is innermost parentheses first.
The innermost parentheses here are in red:

\(\Large \dfrac{6[5\color{red}{(3-9)}-1]+2 }{7(8-2) + 4 }\)

Do what is in red first.

Answer 20

What is 3 - 9 = ?

Answer 21

@gardenGnostic
Are you still here?

Answer 22

You're really close @gardenGnostic Try doing your math again. Make sure you get the positives and negatives right.

Answer 23

gtg
I'll show you how this is done step by step using the order of operations.
Go over it until you understand it.
P - parentheses
E - exponents
MD - multiplications and divisions in the order they appear from left to right
AS - additions and subtraction in the order they appear from left to right

Answer 24

Work inside the innermost parentheses:

\(\Large \dfrac{6[5\color{red}{(3-9)}-1]+2 }{7(8-2) + 4 }\)

\( = \Large \dfrac{6[5\color{red}{(-6)}-1]+2 }{7(8-2) + 4 }\)

Now you have brackets. Work inside the brackets. Do the multiplication first, 5 * -6:

\( = \Large \dfrac{6[-31-1]+2 }{7(8-2) + 4 }\)

The only thing left to do in the brackets is the subtraction, so subtract -31 - 1

\( = \Large \dfrac{6[-31]+2 }{7(8-2) + 4 }\)

Now do the multiplication in the numerator. 6 * -31

\( = \Large \dfrac{-186+2 }{7(8-2) + 4 }\)

Finally we do the addition in the numerator, -186 + 2

\( = \Large \dfrac{-184 }{7(8-2) + 4 }\)

The numerator is done. Now we work on the denominator. We do what is inside the parentheses first. 8 - 2

\(= \Large \dfrac{-184 }{7(6) + 4 }\)

Now we do the multiplication, 7 * 6

\(= \Large \dfrac{-184 }{42 + 4 }\)

Now we do the addition in the denominator, 42 + 44:

\(= \Large \dfrac{-184 }{46 }\)

Finally we do the division that the fraction means -184/46

\(\Large = -4\)

Answer 25

gtg
If you have any questions, ask, and I'll try to answer when I get back.