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Simplify 4 over quantity 2 plus 7 i.
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multiply top and bottom by bottom's conjugate
8 + 28i
? @freckles
Let me get you started: $$ {4\over2}+7={4\over 2}+{2\times 7\over 2}={4+2\times 7\over 2} $$ Can you finish?
Is that an "i" in the end?
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In that case, we have: $$ {4\over2}+7i=2+7i $$
\[\frac{ 4 }{ 2 + 7i }\]
$$ {4\over2+7i}={4\over2+7i}\times {2-7i\over2-7i}={8-28i\over4+49} $$
Note that we multiply by the complex conjugate of \(2-7i\) of the denominator because we want to make the denominator "real."
ty
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