Question

Evaluate.
^3 sqrt -64

-4
4
undefined

Answer 1

cube root (like any nth root, for an odd integer n) is never undefined.

Answer 2

only EVENth root can result in 'i' but ODDth root will not.

Answer 3

now, hint: 4^3=64

Answer 4

so its 4?

Answer 5

well... let's see
4 * 4 * 4 = -64 ?

Answer 6

\(\large \bf \sqrt[3]{-64}\implies \sqrt[3]{-1\cdot 64}\implies \sqrt[3]{-1}\cdot \sqrt[3]{64}\implies \sqrt[3]{(-1)^3}\cdot \sqrt[3]{64}
\)

Answer 7

you are close,
(-4)^3=-64

Answer 8

(you is you, and jdoe is correct. Not that it takes me to verify that)

Answer 9

so -4

Answer 10

yes

Answer 11

One more please, can you tell me what will \(\large\color{black}{ \displaystyle \sqrt[3]{-8} }\) be?

Answer 12

2 ^3 sqrt -1?

Answer 13

(-2)^3=(-8)
just as
2^3=8

Answer 14

so, \(\large\color{slate}{\displaystyle\sqrt[3]{-8}=-2}\)

Answer 15

ohh ok thnx