Algebra 2 Help: A group of people were given a personality test to determine if they were Type A or Type B. The results are shown in the table below: Male Female Type A 55 75 Type B 48 22 Compare P(Male | Type B) with P(Male or Type B). A) P(Male | Type B)> P(Male or Type B) B) P(Male | Type B)< P(Male or Type B) C) P(Male | Type B) = P(Male or Type B) D) There is not enough information.
lol i will close my version
lets compute A) P(Male | Type B)
there are \(48+22=70\) type B of those, \(48\) are male, so P(Male | Type B) = \(\frac{48}{70}\)
Alright.
P(Male or Type B) is next
there are a total of 70 type B, and another 55 males for a total of \(70+55=125\) of one or the otehr
\[55+75+48+22=200\]so P(male or type B) is \(\frac{125}{200}\)
I'm following so far.
which of course reduces to \(\frac{5}{8}\)
compare the two numbers \[\frac{24}{35}\] vs \[\frac{5}{8}\] to see which one is larger and you are done
The 24/35 is larger. . .?
idk i didn't check hold on
yes, it is !
So the answer would be A?
P(Male | Type B)> P(Male or Type B)
yes i believe that is the correct one
Thank You<3
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