Question

Simplify the trig expression

Answer 1

\[\frac{\[\tan\] \sin(-\theta) }{ \cos(-\theta) }\]
Wouldn't this equal
\[\frac{ -\sin \theta }{ -\cos \theta } \]
which is just ..
\[\tan \theta \]

?

Answer 2

ignore the tan in the first equation

Answer 3

@satellite73

Answer 4

@jim_thompson5910

Answer 5

Rules:

cos(-x) = cos(x) for all x
sin(-x) = -sin(x) for all x

Answer 6

\[\Large \frac{\sin(-x)}{\cos(-x)} = \frac{-\sin(x)}{\cos(x)} = -\tan(x)\]

Answer 7

are these the negative identities ?

Answer 8

ohh..i copied the cos identity rule wrong on my book. i see it now, thanks

Answer 9

np