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Mathematics 15 Online
OpenStudy (kj4uts):

Let v= (5, -2) and w= (-10, 4). Which of the following is true? Check all that apply. I think the answers are B. V*W=-58 and D. The y-component of w is 4.

OpenStudy (kj4uts):

jimthompson5910 (jim_thompson5910):

how about A or C?

OpenStudy (kj4uts):

oh ok they might be better choices I am not exactly sure

jimthompson5910 (jim_thompson5910):

well B and D are correct, but did you check out A or C?

OpenStudy (kj4uts):

I did but I am not sure about those two they did not look correct to me but maybe one of them is also?

jimthompson5910 (jim_thompson5910):

are w and v perpendicular? if so, why? if not, then why not?

jimthompson5910 (jim_thompson5910):

think of the formula \[\Large \cos(\theta) = \frac{ \vec{v}\cdot \vec{w}}{|\vec{v}|*|\vec{w}|}\]

OpenStudy (kj4uts):

@jim_thompson5910 im trying to figure it out using the formula but I am still having trouble with using this formula.

jimthompson5910 (jim_thompson5910):

what must theta be if the vectors are perpendicular?

OpenStudy (kj4uts):

isn't θ is the angle between v ⃗ and w ⃗ .

jimthompson5910 (jim_thompson5910):

yes it is

jimthompson5910 (jim_thompson5910):

what must theta be if the vectors are perpendicular?

OpenStudy (kj4uts):

I know that to find a perpendicular vector the dot product must be 0.

jimthompson5910 (jim_thompson5910):

that is correct, so in this case is v dot w = 0 ?

OpenStudy (kj4uts):

I looks to me no?

jimthompson5910 (jim_thompson5910):

yes, it's actually -58

jimthompson5910 (jim_thompson5910):

so the two vectors are NOT perpendicular

jimthompson5910 (jim_thompson5910):

that rules out C, but what about A?

OpenStudy (kj4uts):

The way I would answer this I am not sure if this is right: -2(5, -2)=(-10, 4) so I guess that would make A. an answer also?

jimthompson5910 (jim_thompson5910):

A is correct as well

jimthompson5910 (jim_thompson5910):

So A, B, D

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