Question

How can I solve this rational expressions: p^2 - 1/5p + 25 = p/5

Answer 1

You are looking for a real solution correct?

Answer 2

Yes.

Answer 3

Alright. This will take some time :)!

Answer 4

Okay.

Answer 5

Step 1 is to simplify both sides of the equation. Then we subtract 1/5p from both sides which looks like -> \[p^2 + \frac{ -1 }{ 5 }p + 25 - \frac{ 1 }{ 5 }p = \frac{ 1 }{ 5 }p - \frac{ 1 }{ 5 }p\]

Answer 6

Which turns into what?

Answer 7

Could I factor the equation, or should I not?

Answer 8

Do not factor.

Answer 9

So this transfers to -> \[p^2 + \frac{ -2 }{ 5 }p + 25 = 0\]

Answer 10

See how i got that?

Answer 11

my approach would be to multiply by 5 and subtract a p ...

Answer 12

Amistre lol.

Answer 13

We are trying to see if it has a real solution or not :) which i already know.

Answer 14

:) youre doing fine then

Answer 15

@5jackyh do you see how i got that last answer?

Answer 16

?

Answer 17

I'm working on it.

Answer 18

Mkay. Because for the next part we are using the quadratic formula where a = 1 , b = -0.4, c = 25

Answer 19

You there? :)?

Answer 20

Here is the work for quadratics, based upon this info what would your answer be @5jackyh ?

Answer 21

hmm?

Answer 22

I got it.

Answer 23

What is it :)?

Answer 24

Jack?

Answer 25

Well basically it is so easy as i already gave it out with the quadratics, it would be no real solution.

Answer 26

p^2 - 1/5p + 25 = p/5

5p^2 -p +125 = p

5p^2 -2p +125 = 0
a b c

if b^2 - 4ac is negative, then no real roots :)

4 -4(5)(125) ... yeah, its definitely gonna be negative ....