A nutritionist burns 28 grams of corn chips. The heat released raises 5,000 mL of water from 22°C to 54°C. Complete the table below, assuming the corn chips are completely burned and all the heat is absorbed by the water. Complete the chart for 61 g of tomatoes if the same setup is used and the temperature increases by 4°C.
@JFraser can you help again?
Can anyone help? I'll fan and medal.
it's the same kind of problem as last time, find the energy absorbed by the water
Can you walk me through it?
the mass of water is 5000 g, right?
and the heat capacity of water is always 4.18 J/g°C?
@JFraser
@TheSmartOne can you help?
@Data_LG2
Can anyone help?
@randolal
yes, the specific heat of water is always 4.18 J/gC
okay. that's what I have. How do I find the total energy released?
hello?... @JFraser
the same way you found it last time\[Q = m*C_p * \Delta T\]
what do those stand for? m=mass and what about the others? sorry, the last perosn who helped didn't really explain. he just gave me numbers
@JFraser
m is the mass of water, C_p is the specific heat of water, and \(\Delta T\) is the change in temp.
okay... can the mass stay in g? @JFraser
ohhh m is mass of water? I thought it was the mass of the other thing
so that means my other one is wrong..
if you're using the specific heat of water, then you use the mass of water.
ohhhhhhh okay...
and \(\Delta T\) is the change in temp of the \(water\), so everything is comparing to the same stuff
oh, okay... does the mass stay in g or does it get converted to kg?
it stays in grams, because the specific heat is also in J/gC
ohhhh okay. thanks :)
then to find the amount of heat (in Joules) released by the combustion you do what?...
the heat released is the \(Q\) in the equation
no, not of the water, of the corn chips and tomatoes?
the heat released by the chips must be \(absorbed\) by the water, that's why you use the water, not the mass of chips first
wait, now I'm confused... I know how to find it in the water, but then I have to use that to find it in the corn chips.. how do I do that?
the energy will be equal
the energy \(lost\) by the burning chips must be \(gained\) by the water, which is why it heats up
so why in the other one did I put g/J?
I'm still confused. I'm sorry :/ you must be getting impatient with me.
i don't know, but that's upside down
what's upside down?
oops* I meant J/g
it should be J/g, but you're comparing two different substances: the chips, and the tomatoes. Each one is burned, and each one releases energy when it burns. The J/g RATIO of each substance is what you're asked to find
... I'm lost.
ok, let me see if i can start again in steps
okay.. thanks.
I'm sorry cx
when the chips burn, they release energy, ok?
when the chips \(release \) energy, the water \(absorbs\) it
yes..
ok
the \(amount\) of energy that the water absorbs will be \(equal \space to\) the energy released by the chips the \(amount\) of energy absorbed by the water will be \[Q = m*C_p*\Delta T\] m is the mass of the water, C_p is the specific heat of water, and (\Delta T\) is the change in temp of the water and you have all 3 of those values, so multiply them all together and get your amount of energy
and it's the same? I got 668800...
J that is
yes, 668,800J of energy are \(released\) from 28g of chips when burned
how many Joules are released \(per \space gram\) of chips?
do I need to do that for the question?
\[\frac{J}{g} = \frac{668,000J}{28g \space of \space chips}\]
yes, for the last part
and I know how to do that.. it's 23885.714.. J/g
but the question is How much heat (in Joules) is released by the combustion of the corn chips?
you already found that, its 668,800J. because Joules is energy
okay, exactly
and for tomatoes I got 83600 J
now find the J/g for the \(tomatoes\) just like you did for the chips
but why do I need to do that?
because the last part of the question asks you to
no it doesn't?...
read the last part, it does
compare the calories in one gram of tomatoes to the calories in one gram of corn chips
that's the last part
so do you still need to do that? that's why I'm so confused, I think
@JFraser
you have 2 different substances, each released a different amount of energy. it's not useful to compare energy unless you're doing it \(per \space gram\) or \(per \space ounce\) of each substance. The question is kind of backwards because it just asks you to convert to calories just to compare the chips and tomatoes.
how do I convert to calories? I don't understand the explanation it gives..
1 calorie = 4.184J, so take each amount of energy, and divide each one by 4.184, to convert the unit J into a unit of calorie
so\[668,800 \cancel{Joules} * \frac{1 calorie}{4.184 \cancel{Joules}}\]
do the same thing to the tomatoes energy
oh.. so for the chips it's 159847.0363?
that's illogical.. did I do something wrong?
there's too many decimals, look at your sigfigs
thanks for the help! :D
it's 160,000 calories, which is correct
now that's for the \(total\) sample of chips. Divide the 160,000 calories by 28grams, and you have the amount of \(calories \space per \space gram\) for the chips, and do the same thing for the tomatoes
ohhhhhhh dang. okay.
what you have is basically: 28g of chips release 160,000 calories. 61g of tomatoes release 20,000 calories
why'd you round?
because i'm lazy
so I shouldn't round?
for chips I got 5708.8 cal/g... is that right?
the difference between 159,847J and 160,000J is practically zero.
that's what i get, GJ
wait, why do you need the difference?
you don't, i'm explaining why i'm rounding
nevermind.. that was a dumb question.
i figured it out XD before I saw that
for tomatoes it's 327.56cal/g right?
so that's it? I'm done?
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