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Mathematics 17 Online
OpenStudy (anonymous):

solve the system of equations.

OpenStudy (anonymous):

OpenStudy (anonymous):

@kirbykirby

OpenStudy (anonymous):

he is great he can help you, not only so you get the answer but you understand it

OpenStudy (amorfide):

you know what y is so substitute it into the other equation and simplify to work out the x value, then substitute x back into the first equation

OpenStudy (amorfide):

for example

OpenStudy (amorfide):

\[y= 2x ^{2} -3\] \[y=3x-1\] We know Y so \[2x ^{2}-3=3x-1\]

OpenStudy (anonymous):

i think its a but im not sure. i just need someone to tell me if im wrong or not.

OpenStudy (amorfide):

then you just solve the quadratic, get the x values, and then sub your x values into one of the original equations to get your y values

OpenStudy (anonymous):

so its b?

OpenStudy (kirbykirby):

no wait..

OpenStudy (kirbykirby):

I sort of ignored the "no solution" answer

OpenStudy (kirbykirby):

what did you find as your x-values?

OpenStudy (anonymous):

i was thinking it was no solution because i worked the problem out. i just wanted someone to double check.

OpenStudy (kirbykirby):

Well there is a solution =]

OpenStudy (anonymous):

my other thought would be B.

OpenStudy (amorfide):

b is correct isn't it?

OpenStudy (kirbykirby):

Well not quite. Just substitute \(x=-1/2\) and you don't get y=5

OpenStudy (anonymous):

so which is it? @kirbykirby

OpenStudy (amorfide):

oh I didn't see "no solution" lmao

OpenStudy (amorfide):

the answer will be (-1/2, -5/2) (2,5)

OpenStudy (kirbykirby):

I did the same mistake not seeing "no solution" at first xD @amorfide But yeah you're right =]

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